[Cryptography] RFC: block cipher randomization
Vlad
gluk256 at gmail.com
Mon Jun 27 09:11:58 EDT 2016
> (1) Assuming your Gamma is random, doesnâ€™t this results in 2-to-1
> ciphertext, expansion?
>
> (2) How do you generate a given Gamma for a potentially unlimited amount
> of plaintext?
>
>
1. Yes, it does mean ciphertext expansion, on average 2:1.
2. E.g. a hash chain. Calculate a hash of initial value, save the resulting
value, then calculate the hash of this resulting value, and so on,
unlimited.
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