[Cryptography] Photon beam splitters for "true" random number generation ?
ben at links.org
Mon Dec 14 16:27:24 EST 2015
On Sun, 13 Dec 2015 at 04:31 Henry Baker <hbaker1 at pipeline.com> wrote:
> I'm not a physicist, but I recall from my undergraduate days that one can
> produce a beam of essentially "pure" linearly polarized light.
> Furthermore, if one then splits this linearly polarized beam into two and
> passes one through another linear polarizer at 45 degrees and the other
> beam goes through a different linear polarizer also at 45 degrees to the
> first beam, but 90 degrees to the other polarizer, then each photon that
> gets through at all, must *randomly choose* whether it will align with the
> first polarizer or the second polarizer.
> We then *detect* these photons by positioning a detector behind the first
> polarizer and another detector behind the second polarizer. We call the
> first detector the "0" detector and the second detector the "1" detector.
As soon as you do that, the quantum effects disappear so you're now relying
on the perfection of your beam splitter. You haven't said how that works,
-------------- next part --------------
An HTML attachment was scrubbed...
More information about the cryptography